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Solution To The “Marvin Is 3 More Than Twice The Age Of Antony” Age Problem

AGE PROBLEMS – In this article, we are going to answer the algebra problem that goes “Marvin is 3 more than twice the age of Antony, in 10 years, the sum of their ages will be 47. How old are they?​”.

The answer is Marvin’s age is 19 and Antony is 8. Here is the step by step solution to solving the age problem of Marvin and Antony.

Marvin Is 3 More Than Twice The Age Of Antony In 10 Years (SOLUTION)
Image from: NY Times

First, we need to set a variable for Antony and Marvin’s age. We could let Anthony’s be “x” and Since Marvin is 3 more than twice the age of Antony, Marvin’s age could be equated to 2x+3 (twice the age of Antony(x) + 3 years).

Now, the questions states that in 10 years, the sums of their ages would be equal to 47. Therefore, we could say that: Antony’s age in 10 years [(x+10) + (2x+3) + 10 ] = 47.

Next, we just need to solve for x!

x+10 + 2x+3 + 10 = 47
3x + 23 = 47
3x = 47 – 23
3x= 24
x= 24/3
x= 8 is Anthony’s age.

To solve for Marvin’s age, we simply need to input Anthony’s age in the formula for Marvin.

2x+3 = Marvin’s Age ; x=8
2(8) + 3 = Marvin’s Age
16 + 3 = Marvin’s Age
19 = Marvin’s Age.

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