Solution To The “Marvin Is 3 More Than Twice The Age Of Antony” Age Problem
AGE PROBLEMS – In this article, we are going to answer the algebra problem that goes “Marvin is 3 more than twice the age of Antony, in 10 years, the sum of their ages will be 47. How old are they?”.
The answer is Marvin’s age is 19 and Antony is 8. Here is the step by step solution to solving the age problem of Marvin and Antony.
First, we need to set a variable for Antony and Marvin’s age. We could let Anthony’s be “x” and Since Marvin is 3 more than twice the age of Antony, Marvin’s age could be equated to 2x+3 (twice the age of Antony(x) + 3 years).
Now, the questions states that in 10 years, the sums of their ages would be equal to 47. Therefore, we could say that: Antony’s age in 10 years [(x+10) + (2x+3) + 10 ] = 47.
Next, we just need to solve for x!
x+10 + 2x+3 + 10 = 47
3x + 23 = 47
3x = 47 – 23
3x= 24
x= 24/3
x= 8 is Anthony’s age.
To solve for Marvin’s age, we simply need to input Anthony’s age in the formula for Marvin.
2x+3 = Marvin’s Age ; x=8
2(8) + 3 = Marvin’s Age
16 + 3 = Marvin’s Age
19 = Marvin’s Age.
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