# Twice A Number Increased By 5 Algebra Problem Solutions

## Algebra Problem: Twice A Number Increased By 5 Solution

BASIC ALGEBRA QUESTIONS – In this article, we are going to answer the problem that goes “Twice a number increased by 5 is the same as three times the number decreased by 8“. Find the number.

This worded algebra question is pretty easy to solve, all we need to do is go through each of the steps. But first, we need to understand exactly what is being asked in the question so we could identify the variables.

Here is the step-by-step solution to the problem:

We are asked to find the number, so, we could assign the number as “x”. Next, the problem says that “x” would be equal to twice a number added by 5. This gives us: “2x+5”.

Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. With this, we get: “3x-8”.

To finalize, we are told that both of these cases are equal to each other. So, all we need to do is equate the formulas to one another and solve for “x”.

2x + 5 = 3x-8
3x – 2x = 5 + 8
x = 13 is the answer to the problem.

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