Abigail Is 8 Years Older Than Cynthia (Answers To Age Problem)
AGE PROBLEMS – In this article, we are going to learn the answer to the age problem: Abigail is 8 years older than Cynthia.
The full question goes: Abigail is 8 years older than Cynthia. Twenty years ago Abigail was three times as old as Cynthia was. How old is each of them now?
To answer this question we need to identify the variables and assign the age values to them. First, we can see that there are two timelines – the Present, and 20 years ago. We need to put that into our equation.
The equation would be A = X+8 (Present) and C = X. This equation accounts for the ages of Abigail and Cynthia in the present.
Next, we solve for their ages 20 years ago. The equation should look like: A = 3(X-20) (three times older than Cynthia 20 years ago) and C = X-20.
Afterward, we solve for the values of X. To do that, we need to equate their ages now and their ages 20 years ago.
Cynthia = 8 + x – 20
Abigail = 3(x-20)
8 + x – 20 = 3 (x – 20)8 + x – 20 = 3 (x – 20)
x – 12 = 3x – 60
-3x + x = -60 + 12
-2x = -48
-2x/-2 = -48/-2
x = 24
Afterward, we place the value of X back to the formula. Therefore, Cynthia would be = 24 years old.
Next, Abigail would be 24 + 8 = 32 years old.
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